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5-11x^2=8x
We move all terms to the left:
5-11x^2-(8x)=0
a = -11; b = -8; c = +5;
Δ = b2-4ac
Δ = -82-4·(-11)·5
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{71}}{2*-11}=\frac{8-2\sqrt{71}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{71}}{2*-11}=\frac{8+2\sqrt{71}}{-22} $
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